| << Chapter < Page | Chapter >> Page > |
| The Second Law of Thermodynamics | |
|---|---|
| Δ S univ >0 | spontaneous |
| Δ S univ <0 | nonspontaneous (spontaneous in opposite direction) |
| Δ S univ = 0 | reversible (system is at equilibrium) |
For many realistic applications, the surroundings are vast in comparison to the system. In such cases, the heat gained or lost by the surroundings as a result of some process represents a very small, nearly infinitesimal, fraction of its total thermal energy. For example, combustion of a fuel in air involves transfer of heat from a system (the fuel and oxygen molecules undergoing reaction) to surroundings that are infinitely more massive (the earth’s atmosphere). As a result, q surr is a good approximation of q rev , and the second law may be stated as the following:
We may use this equation to predict the spontaneity of a process as illustrated in [link] .
is 22.1 J/K and requires that the surroundings transfer 6.00 kJ of heat to the system. Is the process spontaneous at −10.00 °C? Is it spontaneous at +10.00 °C?
At −10.00 °C (263.15 K), the following is true:
S univ <0, so melting is nonspontaneous ( not spontaneous) at −10.0 °C.
At 10.00 °C (283.15 K), the following is true:
S univ >0, so melting is spontaneous at 10.00 °C.
Entropy is a state function, and freezing is the opposite of melting. At −10.00 °C spontaneous, +0.7 J/K; at +10.00 °C nonspontaneous, −0.9 J/K.
The previous section described the various contributions of matter and energy dispersal that contribute to the entropy of a system. With these contributions in mind, consider the entropy of a pure, perfectly crystalline solid possessing no kinetic energy (that is, at a temperature of absolute zero, 0 K). This system may be described by a single microstate, as its purity, perfect crystallinity and complete lack of motion means there is but one possible location for each identical atom or molecule comprising the crystal ( W = 1). According to the Boltzmann equation, the entropy of this system is zero.
This limiting condition for a system’s entropy represents the third law of thermodynamics : the entropy of a pure, perfect crystalline substance at 0 K is zero.
We can make careful calorimetric measurements to determine the temperature dependence of a substance’s entropy and to derive absolute entropy values under specific conditions. Standard entropies are given the label for values determined for one mole of substance at a pressure of 1 bar and a temperature of 298 K. The standard entropy change (Δ S °) for any process may be computed from the standard entropies of its reactant and product species like the following:
Notification Switch
Would you like to follow the 'Chemistry' conversation and receive update notifications?
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|