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Arc Length = lim n i = 1 n 1 + [ f ( x i * ) ] 2 Δ x = a b 1 + [ f ( x ) ] 2 d x .

We summarize these findings in the following theorem.

Arc length for y = f ( x )

Let f ( x ) be a smooth function over the interval [ a , b ] . Then the arc length of the portion of the graph of f ( x ) from the point ( a , f ( a ) ) to the point ( b , f ( b ) ) is given by

Arc Length = a b 1 + [ f ( x ) ] 2 d x .

Note that we are integrating an expression involving f ( x ) , so we need to be sure f ( x ) is integrable. This is why we require f ( x ) to be smooth. The following example shows how to apply the theorem.

Calculating the arc length of a function of x

Let f ( x ) = 2 x 3 / 2 . Calculate the arc length of the graph of f ( x ) over the interval [ 0 , 1 ] . Round the answer to three decimal places.

We have f ( x ) = 3 x 1 / 2 , so [ f ( x ) ] 2 = 9 x . Then, the arc length is

Arc Length = a b 1 + [ f ( x ) ] 2 d x = 0 1 1 + 9 x d x .

Substitute u = 1 + 9 x . Then, d u = 9 d x . When x = 0 , then u = 1 , and when x = 1 , then u = 10 . Thus,

Arc Length = 0 1 1 + 9 x d x = 1 9 0 1 1 + 9 x 9 d x = 1 9 1 10 u d u = 1 9 · 2 3 u 3 / 2 | 1 10 = 2 27 [ 10 10 1 ] 2.268 units .
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Let f ( x ) = ( 4 / 3 ) x 3 / 2 . Calculate the arc length of the graph of f ( x ) over the interval [ 0 , 1 ] . Round the answer to three decimal places.

1 6 ( 5 5 1 ) 1.697

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Although it is nice to have a formula for calculating arc length, this particular theorem can generate expressions that are difficult to integrate. We study some techniques for integration in Introduction to Techniques of Integration . In some cases, we may have to use a computer or calculator to approximate the value of the integral.

Using a computer or calculator to determine the arc length of a function of x

Let f ( x ) = x 2 . Calculate the arc length of the graph of f ( x ) over the interval [ 1 , 3 ] .

We have f ( x ) = 2 x , so [ f ( x ) ] 2 = 4 x 2 . Then the arc length is given by

Arc Length = a b 1 + [ f ( x ) ] 2 d x = 1 3 1 + 4 x 2 d x .

Using a computer to approximate the value of this integral, we get

1 3 1 + 4 x 2 d x 8.26815 .
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Let f ( x ) = sin x . Calculate the arc length of the graph of f ( x ) over the interval [ 0 , π ] . Use a computer or calculator to approximate the value of the integral.

Arc Length 3.8202

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Arc length of the curve x = g ( y )

We have just seen how to approximate the length of a curve with line segments. If we want to find the arc length of the graph of a function of y , we can repeat the same process, except we partition the y -axis instead of the x -axis . [link] shows a representative line segment.

This figure is a graph. It is a curve to the right of the y-axis beginning at the point g(ysubi-1). The curve ends in the first quadrant at the point g(ysubi). Between the two points on the curve is a line segment. A right triangle is formed with this line segment as the hypotenuse, a horizontal segment with length delta x, and a vertical line segment with length delta y.
A representative line segment over the interval [ y i 1 , y i ] .

Then the length of the line segment is ( Δ y ) 2 + ( Δ x i ) 2 , which can also be written as Δ y 1 + ( ( Δ x i ) / ( Δ y ) ) 2 . If we now follow the same development we did earlier, we get a formula for arc length of a function x = g ( y ) .

Arc length for x = g ( y )

Let g ( y ) be a smooth function over an interval [ c , d ] . Then, the arc length of the graph of g ( y ) from the point ( c , g ( c ) ) to the point ( d , g ( d ) ) is given by

Arc Length = c d 1 + [ g ( y ) ] 2 d y .

Calculating the arc length of a function of y

Let g ( y ) = 3 y 3 . Calculate the arc length of the graph of g ( y ) over the interval [ 1 , 2 ] .

We have g ( y ) = 9 y 2 , so [ g ( y ) ] 2 = 81 y 4 . Then the arc length is

Arc Length = c d 1 + [ g ( y ) ] 2 d y = 1 2 1 + 81 y 4 d y .

Using a computer to approximate the value of this integral, we obtain

1 2 1 + 81 y 4 d y 21.0277 .
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Let g ( y ) = 1 / y . Calculate the arc length of the graph of g ( y ) over the interval [ 1 , 4 ] . Use a computer or calculator to approximate the value of the integral.

Arc Length = 3.15018

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Source:  OpenStax, Calculus volume 1. OpenStax CNX. Feb 05, 2016 Download for free at http://cnx.org/content/col11964/1.2
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