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  • Set up and solve optimization problems in several applied fields.

One common application of calculus is calculating the minimum or maximum value of a function. For example, companies often want to minimize production costs or maximize revenue. In manufacturing, it is often desirable to minimize the amount of material used to package a product with a certain volume. In this section, we show how to set up these types of minimization and maximization problems and solve them by using the tools developed in this chapter.

Solving optimization problems over a closed, bounded interval

The basic idea of the optimization problems    that follow is the same. We have a particular quantity that we are interested in maximizing or minimizing. However, we also have some auxiliary condition that needs to be satisfied. For example, in [link] , we are interested in maximizing the area of a rectangular garden. Certainly, if we keep making the side lengths of the garden larger, the area will continue to become larger. However, what if we have some restriction on how much fencing we can use for the perimeter? In this case, we cannot make the garden as large as we like. Let’s look at how we can maximize the area of a rectangle subject to some constraint on the perimeter.

Maximizing the area of a garden

A rectangular garden is to be constructed using a rock wall as one side of the garden and wire fencing for the other three sides ( [link] ). Given 100 ft of wire fencing, determine the dimensions that would create a garden of maximum area. What is the maximum area?

A drawing of a garden has x and y written on the vertical and horizontal sides, respectively. There is a rock wall running along the entire bottom horizontal length of the drawing.
We want to determine the measurements x and y that will create a garden with a maximum area using 100 ft of fencing.

Let x denote the length of the side of the garden perpendicular to the rock wall and y denote the length of the side parallel to the rock wall. Then the area of the garden is

A = x · y .

We want to find the maximum possible area subject to the constraint that the total fencing is 100 ft . From [link] , the total amount of fencing used will be 2 x + y . Therefore, the constraint equation is

2 x + y = 100 .

Solving this equation for y , we have y = 100 2 x . Thus, we can write the area as

A ( x ) = x · ( 100 2 x ) = 100 x 2 x 2 .

Before trying to maximize the area function A ( x ) = 100 x 2 x 2 , we need to determine the domain under consideration. To construct a rectangular garden, we certainly need the lengths of both sides to be positive. Therefore, we need x > 0 and y > 0 . Since y = 100 2 x , if y > 0 , then x < 50 . Therefore, we are trying to determine the maximum value of A ( x ) for x over the open interval ( 0 , 50 ) . We do not know that a function necessarily has a maximum value over an open interval. However, we do know that a continuous function has an absolute maximum (and absolute minimum) over a closed interval. Therefore, let’s consider the function A ( x ) = 100 x 2 x 2 over the closed interval [ 0 , 50 ] . If the maximum value occurs at an interior point, then we have found the value x in the open interval ( 0 , 50 ) that maximizes the area of the garden. Therefore, we consider the following problem:

Maximize A ( x ) = 100 x 2 x 2 over the interval [ 0 , 50 ] .

As mentioned earlier, since A is a continuous function on a closed, bounded interval, by the extreme value theorem, it has a maximum and a minimum. These extreme values occur either at endpoints or critical points. At the endpoints, A ( x ) = 0 . Since the area is positive for all x in the open interval ( 0 , 50 ) , the maximum must occur at a critical point. Differentiating the function A ( x ) , we obtain

A ( x ) = 100 4 x .

Therefore, the only critical point is x = 25 ( [link] ). We conclude that the maximum area must occur when x = 25 . Then we have y = 100 2 x = 100 2 ( 25 ) = 50 . To maximize the area of the garden, let x = 25 ft and y = 50 ft . The area of this garden is 1250 ft 2 .

The function A(x) = 100x – 2x is graphed. At its maximum there is an intersection of two dashed lines and text that reads “Maximum area is 1250 square feet when x = 25 feet.”
To maximize the area of the garden, we need to find the maximum value of the function A ( x ) = 100 x 2 x 2 .
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Questions & Answers

What is a independent variable
Sifiso Reply
a variable that does not depend on another.
solve number one step by step
bil Reply
how to prove 1-sinx/cos x= cos x/-1+sin x?
Rochel Reply
1-sin x/cos x= cos x/-1+sin x
how to prove 1-sun x/cos x= cos x / -1+sin x?
how to prove tan^2 x=csc^2 x tan^2 x-1?
Rochel Reply
divide by tan^2 x giving 1=csc^2 x -1/tan^2 x, rewrite as: 1=1/sin^2 x -cos^2 x/sin^2 x, multiply by sin^2 x giving: sin^2 x=1-cos^2x. rewrite as the familiar sin^2 x + cos^2x=1 QED
how to prove sin x - sin x cos^2 x=sin^3x?
Rochel Reply
sin x - sin x cos^2 x sin x (1-cos^2 x) note the identity:sin^2 x + cos^2 x = 1 thus, sin^2 x = 1 - cos^2 x now substitute this into the above: sin x (sin^2 x), now multiply, yielding: sin^3 x Q.E.D.
take sin x common. you are left with 1-cos^2x which is sin^2x. multiply back sinx and you get sin^3x.
Left side=sinx-sinx cos^2x =sinx-sinx(1+sin^2x) =sinx-sinx+sin^3x =sin^3x thats proved.
how to prove tan^2 x/tan^2 x+1= sin^2 x
not a bad question
what is function.
Nawaz Reply
what is polynomial
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
a term/algebraic expression raised to a non-negative integer power and a multiple of co-efficient,,,,,, T^n where n is a non-negative,,,,, 4x^2
An expression in which power of all the variables are whole number . such as 2x+3 5 is also a polynomial of degree 0 and can be written as 5x^0
what is hyperbolic function
vector Reply
find volume of solid about y axis and y=x^3, x=0,y=1
amisha Reply
3 pi/5
what is the power rule
Vanessa Reply
Is a rule used to find a derivative. For example the derivative of y(x)= a(x)^n is y'(x)= a*n*x^n-1.
how do i deal with infinity in limits?
Itumeleng Reply
Add the functions f(x)=7x-x g(x)=5-x
Julius Reply
f(x)=7x-x g(x)=5-x
what is domain
Cabdalla Reply
difference btwn domain co- domain and range
The set of inputs of a function. x goes in the function, y comes out.
where u from verna
If you differentiate then answer is not x
domain is the set of values of independent variable and the range is the corresponding set of values of dependent variable
what is functions
mahin Reply
give different types of functions.
how would u find slope of tangent line to its inverse function, if the equation is x^5+3x^3-4x-8 at the point(-8,1)
riyad Reply
pls solve it i Want to see the answer
differentiate each term
why do we need to study functions?
abigail Reply
to understand how to model one variable as a direct relationship to another variable
Practice Key Terms 1

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