# 1.5 Exponential and logarithmic functions  (Page 4/17)

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The exponential function $f\left(x\right)={b}^{x}$ is one-to-one, with domain $\left(\text{−}\infty ,\infty \right)$ and range $\left(0,\infty \right).$ Therefore, it has an inverse function, called the logarithmic function with base $b.$ For any $b>0,b\ne 1,$ the logarithmic function with base b , denoted ${\text{log}}_{b},$ has domain $\left(0,\infty \right)$ and range $\left(\text{−}\infty ,\infty \right),$ and satisfies

${\text{log}}_{b}\left(x\right)=y\phantom{\rule{0.2em}{0ex}}\text{if and only if}\phantom{\rule{0.2em}{0ex}}{b}^{y}=x.$

For example,

$\begin{array}{cccc}{\text{log}}_{2}\left(8\right)=3\hfill & & & \text{since}\phantom{\rule{3em}{0ex}}{2}^{3}=8,\hfill \\ {\text{log}}_{10}\left(\frac{1}{100}\right)=-2\hfill & & & \text{since}\phantom{\rule{3em}{0ex}}{10}^{-2}=\frac{1}{{10}^{2}}=\frac{1}{100},\hfill \\ {\text{log}}_{b}\left(1\right)=0\hfill & & & \text{since}\phantom{\rule{3em}{0ex}}{b}^{0}=1\phantom{\rule{0.2em}{0ex}}\text{for any base}\phantom{\rule{0.2em}{0ex}}b>0.\hfill \end{array}$

Furthermore, since $y={\text{log}}_{b}\left(x\right)$ and $y={b}^{x}$ are inverse functions,

${\text{log}}_{b}\left({b}^{x}\right)=x\phantom{\rule{0.2em}{0ex}}\text{and}\phantom{\rule{0.2em}{0ex}}{b}^{{\text{log}}_{b}\left(x\right)}=x.$

The most commonly used logarithmic function is the function ${\text{log}}_{e}.$ Since this function uses natural $e$ as its base, it is called the natural logarithm    . Here we use the notation $\text{ln}\left(x\right)$ or $\text{ln}\phantom{\rule{0.1em}{0ex}}x$ to mean ${\text{log}}_{e}\left(x\right).$ For example,

$\text{ln}\left(e\right)={\text{log}}_{e}\left(e\right)=1,\text{ln}\left({e}^{3}\right)={\text{log}}_{e}\left({e}^{3}\right)=3,\text{ln}\left(1\right)={\text{log}}_{e}\left(1\right)=0.$

Since the functions $f\left(x\right)={e}^{x}$ and $g\left(x\right)=\text{ln}\left(x\right)$ are inverses of each other,

$\text{ln}\left({e}^{x}\right)=x\phantom{\rule{0.2em}{0ex}}\text{and}\phantom{\rule{0.2em}{0ex}}{e}^{\text{ln}\phantom{\rule{0.1em}{0ex}}x}=x,$

and their graphs are symmetric about the line $y=x$ ( [link] ).

At this site you can see an example of a base-10 logarithmic scale.

In general, for any base $b>0,b\ne 1,$ the function $g\left(x\right)={\text{log}}_{b}\left(x\right)$ is symmetric about the line $y=x$ with the function $f\left(x\right)={b}^{x}.$ Using this fact and the graphs of the exponential functions, we graph functions ${\text{log}}_{b}$ for several values of $b>1$ ( [link] ).

Before solving some equations involving exponential and logarithmic functions, let’s review the basic properties of logarithms.

## Rule: properties of logarithms

If $a,b,c>0,b\ne 1,$ and $r$ is any real number, then

$\begin{array}{cccc}1.\phantom{\rule{2em}{0ex}}{\text{log}}_{b}\left(ac\right)={\text{log}}_{b}\left(a\right)+{\text{log}}_{b}\left(c\right)\hfill & & & \text{(Product property)}\hfill \\ 2.\phantom{\rule{2em}{0ex}}{\text{log}}_{b}\left(\frac{a}{c}\right)={\text{log}}_{b}\left(a\right)-{\text{log}}_{b}\left(c\right)\hfill & & & \text{(Quotient property)}\hfill \\ 3.\phantom{\rule{2em}{0ex}}{\text{log}}_{b}\left({a}^{r}\right)=r{\text{log}}_{b}\left(a\right)\hfill & & & \text{(Power property)}\hfill \end{array}$

## Solving equations involving exponential functions

Solve each of the following equations for $x.$

1. ${5}^{x}=2$
2. ${e}^{x}+6{e}^{\text{−}x}=5$
1. Applying the natural logarithm function to both sides of the equation, we have
$\text{ln}{5}^{x}=\text{ln}\phantom{\rule{0.1em}{0ex}}2.$

Using the power property of logarithms,
$x\phantom{\rule{0.1em}{0ex}}\text{ln}\phantom{\rule{0.1em}{0ex}}5=\text{ln}\phantom{\rule{0.1em}{0ex}}2.$

Therefore, $x=\text{ln}\phantom{\rule{0.1em}{0ex}}2\text{/}\text{ln}\phantom{\rule{0.1em}{0ex}}5.$
2. Multiplying both sides of the equation by ${e}^{x},$ we arrive at the equation
${e}^{2x}+6=5{e}^{x}.$

Rewriting this equation as
${e}^{2x}-5{e}^{x}+6=0,$

we can then rewrite it as a quadratic equation in ${e}^{x}\text{:}$
${\left({e}^{x}\right)}^{2}-5\left({e}^{x}\right)+6=0.$

Now we can solve the quadratic equation. Factoring this equation, we obtain
$\left({e}^{x}-3\right)\left({e}^{x}-2\right)=0.$

Therefore, the solutions satisfy ${e}^{x}=3$ and ${e}^{x}=2.$ Taking the natural logarithm of both sides gives us the solutions $x=\text{ln}\phantom{\rule{0.1em}{0ex}}3,\text{ln}\phantom{\rule{0.1em}{0ex}}2.$

Solve ${e}^{2x}\text{/}\left(3+{e}^{2x}\right)=1\text{/}2.$

$x=\frac{\text{ln}\phantom{\rule{0.1em}{0ex}}3}{2}$

## Solving equations involving logarithmic functions

Solve each of the following equations for $x.$

1. $\text{ln}\left(\frac{1}{x}\right)=4$
2. ${\text{log}}_{10}\sqrt{x}+{\text{log}}_{10}x=2$
3. $\text{ln}\left(2x\right)-3\phantom{\rule{0.1em}{0ex}}\text{ln}\left({x}^{2}\right)=0$
1. By the definition of the natural logarithm function,
$\text{ln}\left(\frac{1}{x}\right)=4\phantom{\rule{0.2em}{0ex}}\text{if and only if}\phantom{\rule{0.2em}{0ex}}{e}^{4}=\frac{1}{x}.$

Therefore, the solution is $x=1\text{/}{e}^{4}.$
2. Using the product and power properties of logarithmic functions, rewrite the left-hand side of the equation as
${\text{log}}_{10}\sqrt{x}+{\text{log}}_{10}x={\text{log}}_{10}x\sqrt{x}={\text{log}}_{10}{x}^{3\text{/}2}=\frac{3}{2}{\text{log}}_{10}x.$

Therefore, the equation can be rewritten as
$\frac{3}{2}{\text{log}}_{10}x=2\phantom{\rule{0.2em}{0ex}}\text{or}\phantom{\rule{0.2em}{0ex}}{\text{log}}_{10}x=\frac{4}{3}.$

The solution is $x={10}^{4\text{/}3}=10\sqrt[3]{10}.$
3. Using the power property of logarithmic functions, we can rewrite the equation as $\text{ln}\left(2x\right)-\text{ln}\left({x}^{6}\right)=0.$
Using the quotient property, this becomes
$\text{ln}\left(\frac{2}{{x}^{5}}\right)=0.$

Therefore, $2\text{/}{x}^{5}=1,$ which implies $x=\sqrt[5]{2}.$ We should then check for any extraneous solutions.

why n does not equal -1
Andrew
I agree with Andrew
Bg
f (x) = a is a function. It's a constant function.
proof the formula integration of udv=uv-integration of vdu.?
Find derivative (2x^3+6xy-4y^2)^2
no x=2 is not a function, as there is nothing that's changing.
are you sure sir? please make it sure and reply please. thanks a lot sir I'm grateful.
The
i mean can we replace the roles of x and y and call x=2 as function
The
if x =y and x = 800 what is y
y=800
800
Bg
how do u factor the numerator?
Nonsense, you factor numbers
Antonio
You can factorize the numerator of an expression. What's the problem there? here's an example. f(x)=((x^2)-(y^2))/2 Then numerator is x squared minus y squared. It's factorized as (x+y)(x-y). so the overall function becomes : ((x+y)(x-y))/2
The
The problem is the question, is not a problem where it is, but what it is
Antonio
I think you should first know the basics man: PS
Vishal
Yes, what factorization is
Antonio
Antonio bro is x=2 a function?
The
Yes, and no.... Its a function if for every x, y=2.... If not is a single value constant
Antonio
you could define it as a constant function if you wanted where a function of "y" defines x f(y) = 2 no real use to doing that though
zach
Why y, if domain its usually defined as x, bro, so you creates confusion
Antonio
Its f(x) =y=2 for every x
Antonio
Yes but he said could you put x = 2 as a function you put y = 2 as a function
zach
F(y) in this case is not a function since for every value of y you have not a single point but many ones, so there is not f(y)
Antonio
x = 2 defined as a function of f(y) = 2 says for every y x will equal 2 this silly creates a vertical line and is equivalent to saying x = 2 just in a function notation as the user above asked. you put f(x) = 2 this means for every x y is 2 this creates a horizontal line and is not equivalent
zach
The said x=2 and that 2 is y
Antonio
that 2 is not y, y is a variable 2 is a constant
zach
So 2 is defined as f(x) =2
Antonio
No y its constant =2
Antonio
what variable does that function define
zach
the function f(x) =2 takes every input of x within it's domain and gives 2 if for instance f:x -> y then for every x, y =2 giving a horizontal line this is NOT equivalent to the expression x = 2
zach
Yes true, y=2 its a constant, so a line parallel to y axix as function of y
Antonio
Sorry x=2
Antonio
And you are right, but os not a function of x, its a function of y
Antonio
As function of x is meaningless, is not a finction
Antonio
yeah you mean what I said in my first post, smh
zach
I mean (0xY) +x = 2 so y can be as you want, the result its 2 every time
Antonio
OK you can call this "function" on a set {2}, but its a single value function, a constant
Antonio
well as long as you got there eventually
zach
volume between cone z=√(x^2+y^2) and plane z=2
Fatima
It's an integral easy
Antonio
V=1/3 h π (R^2+r2+ r*R(
Antonio
How do we find the horizontal asymptote of a function using limits?
Easy lim f(x) x-->~ =c
Antonio
solutions for combining functions
what is a function? f(x)
one that is one to one, one that passes the vertical line test
Andrew
It's a law f() that to every point (x) on the Domain gives a single point in the codomain f(x)=y
Antonio
is x=2 a function?
The
restate the problem. and I will look. ty
is x=2 a function?
The
What is limit
it's the value a function will take while approaching a particular value
Dan
don ger it
Jeremy
what is a limit?
Dlamini
it is the value the function approaches as the input approaches that value.
Andrew
Thanx
Dlamini
Its' complex a limit It's a metrical and topological natural question... approaching means nothing in math
Antonio
is x=2 a function?
The
3y^2*y' + 2xy^3 + 3y^2y'x^2 = 0 sub in x = 2, and y = 1, isolate y'
what is implicit of y³+x²y³=5 at (2,1)
tel mi about a function. what is it?
Jeremy
A function it's a law, that for each value in the domaon associate a single one in the codomain
Antonio
function is a something which another thing depends upon to take place. Example A son depends on his father. meaning here is the father is function of the son. let the father be y and the son be x. the we say F(X)=Y.
Bg
yes the son on his father
pascal
a function is equivalent to a machine. this machine makes x to create y. thus, y is dependent upon x to be produced. note x is an independent variable
moe
x or y those not matter is just to represent.
Bg