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By the end of this section, you will be able to:
  • Solve quadratic equations by using the Zero Product Property
  • Solve quadratic equations factoring
  • Solve applications modeled by quadratic equations

Before you get started, take this readiness quiz.

  1. Solve: 5 y 3 = 0 .
    If you missed this problem, review [link] .
  2. Solve: 10 a = 0 .
    If you missed this problem, review [link] .
  3. Combine like terms: 12 x 2 6 x + 4 x .
    If you missed this problem, review [link] .
  4. Factor n 3 9 n 2 22 n completely.
    If you missed this problem, review [link] .

We have already solved linear equations, equations of the form a x + b y = c . In linear equations, the variables have no exponents. Quadratic equations are equations in which the variable is squared. Listed below are some examples of quadratic equations:

x 2 + 5 x + 6 = 0 3 y 2 + 4 y = 10 64 u 2 81 = 0 n ( n + 1 ) = 42

The last equation doesn’t appear to have the variable squared, but when we simplify the expression on the left we will get n 2 + n .

The general form of a quadratic equation is a x 2 + b x + c = 0 , with a 0 .

Quadratic equation

An equation of the form a x 2 + b x + c = 0 is called a quadratic equation.

a , b , and c are real numbers and a 0

To solve quadratic equations    we need methods different than the ones we used in solving linear equations. We will look at one method here and then several others in a later chapter.

Solve quadratic equations using the zero product property

We will first solve some quadratic equations by using the Zero Product Property. The Zero Product Property    says that if the product of two quantities is zero, it must be that at least one of the quantities is zero. The only way to get a product equal to zero is to multiply by zero itself.

Zero product property

If a · b = 0 , then either a = 0 or b = 0 or both.

We will now use the Zero Product Property    , to solve a quadratic equation.

How to use the zero product property to solve a quadratic equation

Solve: ( x + 1 ) ( x 4 ) = 0 .

Solution

This table gives the steps for solving (x + 1)(x – 4) = 0. The first step is to set each factor equal to 0. Since it is a product equal to 0, at least one factor must equal 0. x + 1 = 0 or x – 4 = 0. The next step is to solve each linear equation. This gives two solutions, x = −1 or x = 4. The last step is to check both answers by substituting the values for x into the original equation.
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Solve: ( x 3 ) ( x + 5 ) = 0 .

x = 3 , x = −5

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Solve: ( y 6 ) ( y + 9 ) = 0 .

y = 6 , y = −9

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We usually will do a little more work than we did in this last example to solve the linear equations that result from using the Zero Product Property.

Solve: ( 5 n 2 ) ( 6 n 1 ) = 0 .

Solution

This image shows the steps for solving (5 n – 2)(6 n – 1) = 0. First, use the zero factor property to set each factor equal to 0, 5 n – 2 = 0 or 6 n – 1 = 0. Then, solve the equations, n = 2/5 or n = 1/6. Finally, check the answers by substituting the two solutions back into the original equation.
( 5 n 2 ) ( 6 n 1 ) = 0
Use the Zero Product Property to set
each factor to 0.
5 n 2 = 0 6 n 1 = 0
Solve the equations. n = 2 5 n = 1 6
Check your answers.
.

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Solve: ( 3 m 2 ) ( 2 m + 1 ) = 0 .

m = 2 3 , m = 1 2

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Solve: ( 4 p + 3 ) ( 4 p 3 ) = 0 .

p = 3 4 , p = 3 4

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Notice when we checked the solutions that each of them made just one factor equal to zero. But the product was zero for both solutions.

Solve: 3 p ( 10 p + 7 ) = 0 .

Solution

This image shows the steps for solving 3 p (10 p + 7) = 0. The first step is using the zero product property to set each factor equal to 0, 3p = 0 or 10 p + 7 = 0. The next step is solving both equations, p = 0 or p = negative 7/10. Finally, check the solutions by substituting the answers into the original equation.
3 p ( 10 p + 7 ) = 0
Use the Zero Product Property to set
each factor to 0.
3 p = 0 10 p + 7 = 0
Solve the equations. p = 0 10 p = −7
p = 7 10
Check your answers.
.

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Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
Practice Key Terms 2

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Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
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