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By the end of this section, you will be able to:
  • Identify the x - and y - intercepts on a graph
  • Find the x - and y - intercepts from an equation of a line
  • Graph a line using the intercepts

Before you get started, take this readiness quiz.

  1. Solve: 3 · 0 + 4 y = −2 .
    If you missed this problem, review [link] .

Identify the x - and y - intercepts on a graph

Every linear equation can be represented by a unique line that shows all the solutions of the equation. We have seen that when graphing a line by plotting points, you can use any three solutions to graph. This means that two people graphing the line might use different sets of three points.

At first glance, their two lines might not appear to be the same, since they would have different points labeled. But if all the work was done correctly, the lines should be exactly the same. One way to recognize that they are indeed the same line is to look at where the line crosses the x - axis and the y - axis. These points are called the intercepts of the line.

Intercepts of a line

The points where a line crosses the x - axis and the y - axis are called the intercepts of a line    .

Let’s look at the graphs of the lines in [link] .

Four figures, each showing a different straight line on the x y- coordinate plane. The x- axis of the planes runs from negative 7 to 7. The y- axis of the planes runs from negative 7 to 7. Figure a shows a straight line crossing the x- axis at the point (3, 0) and crossing the y- axis at the point (0, 6). The graph is labeled with the equation 2x plus y equals 6. Figure b shows a straight line crossing the x- axis at the point (4, 0) and crossing the y- axis at the point (0, negative 3). The graph is labeled with the equation 3x minus 4y equals 12. Figure c shows a straight line crossing the x- axis at the point (5, 0) and crossing the y- axis at the point (0, negative 5). The graph is labeled with the equation x minus y equals 5. Figure d shows a straight line crossing the x- axis and y- axis at the point (0, 0). The graph is labeled with the equation y equals negative 2x.
Examples of graphs crossing the x-negative axis.

First, notice where each of these lines crosses the x negative axis. See [link] .

Figure The line crosses the x - axis at: Ordered pair of this point
Figure (a) 3 ( 3 , 0 )
Figure (b) 4 ( 4 , 0 )
Figure (c) 5 ( 5 , 0 )
Figure (d) 0 ( 0 , 0 )

Do you see a pattern?

For each row, the y - coordinate of the point where the line crosses the x - axis is zero. The point where the line crosses the x - axis has the form ( a , 0 ) and is called the x - intercept of a line . The x - intercept occurs when y is zero.

Now, let’s look at the points where these lines cross the y - axis. See [link] .

Figure The line crosses the y -axis at: Ordered pair for this point
Figure (a) 6 ( 0 , 6 )
Figure (b) −3 ( 0 , −3 )
Figure (c) −5 ( 0 , 5 )
Figure (d) 0 ( 0 , 0 )

What is the pattern here?

In each row, the x - coordinate of the point where the line crosses the y - axis is zero. The point where the line crosses the y - axis has the form ( 0 , b ) and is called the y- intercept of the line. The y - intercept occurs when x is zero.

x - intercept and y - intercept of a line

The x - intercept is the point ( a , 0 ) where the line crosses the x - axis.

The y - intercept is the point ( 0 , b ) where the line crosses the y - axis.
No Alt Text

Find the x - and y - intercepts on each graph.

Three figures, each showing a different straight line on the x y- coordinate plane. The x- axis of the planes runs from negative 7 to 7. The y- axis of the planes runs from negative 7 to 7. Figure a shows a straight line going through the points (negative 6, 5), (negative 4, 4), (negative 2, 3), (0, 2), (2, 1), (4, 0), and (6, negative 1). Figure b shows a straight line going through the points (0, negative 6), (1, negative 3), (2, 0), (3, 3), and (4, 6). Figure c shows a straight line going through the points (negative 6, 1), (negative 5, 0), (negative 4, negative 1), (negative 3, negative 2), (negative 2, negative 3), (negative 1, negative 4), (0, negative 5), and (1, negative 6).

Solution

  1. The graph crosses the x - axis at the point ( 4 , 0 ) . The x - intercept is ( 4 , 0 ) .
    The graph crosses the y - axis at the point ( 0 , 2 ) . The y - intercept is ( 0 , 2 ) .

  2. The graph crosses the x - axis at the point ( 2 , 0 ) . The x - intercept is ( 2 , 0 )
    The graph crosses the y - axis at the point ( 0 , −6 ) . The y - intercept is ( 0 , −6 ) .

  3. The graph crosses the x - axis at the point ( −5 , 0 ) . The x - intercept is ( −5 , 0 ) .
    The graph crosses the y - axis at the point ( 0 , −5 ) . The y - intercept is ( 0 , −5 ) .
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Find the x - and y - intercepts on the graph.

A figure showing a straight line on the x y- coordinate plane. The x- axis of the plane runs from negative 10 to 10. The y- axis of the planes runs from negative 10 to 10. The straight line goes through the points (negative 8, negative 10), (negative 6, negative 8), (negative 4, negative 6), (negative 2, negative 4), (0, negative 2), (2, 0), (4, 2), (6, 4), (8, 6), and (10, 8).

x - intercept: ( 2 , 0 ) ; y - intercept: ( 0 , −2 )

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Find the x - and y - intercepts on the graph.

The figure shows a straight line on the x y- coordinate plane. The x- axis of the plane runs from negative 10 to 10. The y- axis of the planes runs from negative 10 to 10. The straight line goes through the points (negative 9, 8), (negative 6, 6), (negative 3, 4), (0, 2), (3, 0), (6, negative 2), and (9, negative 4).

x - intercept: ( 3 , 0 ) , y - intercept: ( 0 , 2 )

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Find the x - and y - intercepts from an equation of a line

Recognizing that the x - intercept    occurs when y is zero and that the y - intercept occurs when x is zero, gives us a method to find the intercepts of a line from its equation. To find the x - intercept, let y = 0 and solve for x . To find the y - intercept , let x = 0 and solve for y .

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
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bill
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bill
-24m+3+3mÁ^2
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Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
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x=3-2y
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y=x+3/2
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3x-12y=18
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Grace
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Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
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Practice Key Terms 3

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Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
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