10.5 Graphing quadratic equations  (Page 4/15)

 Page 4 / 15

Find the intercepts of the parabola $y=9{x}^{2}+12x+4.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,4\right);x\text{:}\phantom{\rule{0.2em}{0ex}}\left(-\frac{2}{3},0\right)$

Graph quadratic equations in two variables

Now, we have all the pieces we need in order to graph a quadratic equation in two variables. We just need to put them together. In the next example, we will see how to do this.

How to graph a quadratic equation in two variables

Graph $y={x}^{2}-6x+8$ .

Solution

Graph the parabola $y={x}^{2}+2x-8.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,-8\right)$ ; $x\text{:}\phantom{\rule{0.2em}{0ex}}\left(2,0\right),\left(-4,0\right)$ ;
axis: $x=-1$ ; vertex: $\left(-1,-9\right)$ ;

Graph the parabola $y={x}^{2}-8x+12.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,12\right);\phantom{\rule{0.2em}{0ex}}x\text{:}\phantom{\rule{0.2em}{0ex}}\left(2,0\right),\left(6,0\right);$
axis: $x=4;\phantom{\rule{0.2em}{0ex}}\text{vertex:}\phantom{\rule{0.2em}{0ex}}\left(4,-4\right)$ ;

Graph a quadratic equation in two variables.

1. Write the quadratic equation with $y$ on one side.
2. Determine whether the parabola opens upward or downward.
3. Find the axis of symmetry.
4. Find the vertex.
5. Find the y -intercept. Find the point symmetric to the y -intercept across the axis of symmetry.
6. Find the x -intercepts.
7. Graph the parabola.

We were able to find the x -intercepts in the last example by factoring. We find the x -intercepts in the next example by factoring, too.

Graph $y=\text{−}{x}^{2}+6x-9$ .

Solution

 The equation y has on one side. Since a is $-1$ , the parabola opens downward. To find the axis of symmetry, find $x=-\frac{b}{2a}$ . The axis of symmetry is $x=3.$ The vertex is on the line $x=3.$ Find y when $x=3.$ The vertex is $\left(3,0\right).$ The y -intercept occurs when $x=0.$ Substitute $x=0.$ Simplify. The point $\left(0,-9\right)$ is three units to the left of the line of symmetry. The point three units to the right of the line of symmetry is $\left(6,-9\right).$ Point symmetric to the y- intercept is $\left(6,-9\right)$ The y -intercept is $\left(0,-9\right).$ The x -intercept occurs when $y=0.$ Substitute $y=0.$ Factor the GCF. Factor the trinomial. Solve for x . Connect the points to graph the parabola.

Graph the parabola $y=-3{x}^{2}+12x-12.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,-12\right);\phantom{\rule{0.2em}{0ex}}x\text{:}\phantom{\rule{0.2em}{0ex}}\left(2,0\right);$
axis: $x=2;\phantom{\rule{0.2em}{0ex}}\text{vertex:}\left(2,0\right)$ ;

Graph the parabola $y=25{x}^{2}+10x+1.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,1\right);\phantom{\rule{0.2em}{0ex}}x\text{:}\phantom{\rule{0.2em}{0ex}}\left(-\frac{1}{5},0\right);$
axis: $x=-\frac{1}{5};\phantom{\rule{0.2em}{0ex}}\text{vertex:}\phantom{\rule{0.2em}{0ex}}\left(-\frac{1}{5},0\right)$ ;

For the graph of $y=-{x}^{2}+6x-9$ , the vertex and the x -intercept were the same point. Remember how the discriminant determines the number of solutions of a quadratic equation? The discriminant of the equation $0=\text{−}{x}^{2}+6x-9$ is 0, so there is only one solution. That means there is only one x -intercept, and it is the vertex of the parabola.

How many x -intercepts would you expect to see on the graph of $y={x}^{2}+4x+5$ ?

Graph $y={x}^{2}+4x+5$ .

Solution

 The equation has y on one side. Since a is 1, the parabola opens upward. To find the axis of symmetry, find $x=-\frac{b}{2a}.$ The axis of symmetry is $x=-2.$ The vertex is on the line $x=-2.$ Find y when $x=-2.$ The vertex is $\left(-2,1\right).$ The y -intercept occurs when $x=0.$ Substitute $x=0.$ Simplify. The point $\left(0,5\right)$ is two units to the right of the line of symmetry. The point two units to the left of the line of symmetry is $\left(-4,5\right).$ The y -intercept is $\left(0,5\right).$ Point symmetric to the y- intercept is $\left(-4,5\right)$ . The x - intercept occurs when $y=0.$ Substitute $y=0.$ Test the discriminant. ${b}^{2}-4ac$ ${4}^{2}-4\cdot 15$ $16-20$ $\phantom{\rule{1em}{0ex}}-4$ Since the value of the discriminant is negative, there is no solution and so no x- intercept. Connect the points to graph the parabola. You may want to choose two more points for greater accuracy.

Graph the parabola $y=2{x}^{2}-6x+5.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,5\right);\phantom{\rule{0.2em}{0ex}}x\text{:}\phantom{\rule{0.2em}{0ex}}\text{none};$
axis: $x=\frac{3}{2};\phantom{\rule{0.2em}{0ex}}\text{vertex:}\phantom{\rule{0.2em}{0ex}}\left(\frac{3}{2},\frac{1}{2}\right)$ ;

Graph the parabola $y=-2{x}^{2}-1.$

$y\text{:}\phantom{\rule{0.2em}{0ex}}\left(0,-1\right);x\text{:}\phantom{\rule{0.2em}{0ex}}\text{none};$
axis: $x=0;\phantom{\rule{0.2em}{0ex}}\text{vertex:}\phantom{\rule{0.2em}{0ex}}\left(0,-1\right)$ ;

Questions & Answers

a perfect square v²+2v+_
Dearan Reply
kkk nice
Abdirahman Reply
algebra 2 Inequalities:If equation 2 = 0 it is an open set?
Kim Reply
or infinite solutions?
Kim
y=10×
Embra Reply
if |A| not equal to 0 and order of A is n prove that adj (adj A = |A|
Nancy Reply
rolling four fair dice and getting an even number an all four dice
ramon Reply
Kristine 2*2*2=8
Bridget Reply
Differences Between Laspeyres and Paasche Indices
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No. 7x -4y is simplified from 4x + (3y + 3x) -7y
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is it 3×y ?
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J, combine like terms 7x-4y
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f(x)= 2|x+5| find f(-6)
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f(n)= 2n + 1
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Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
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. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
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At high concentrations (>0.01 M), the relation between absorptivity coefficient and absorbance is no longer linear. This is due to the electrostatic interactions between the quantum dots in close proximity. If the concentration of the solution is high, another effect that is seen is the scattering of light from the large number of quantum dots. This assumption only works at low concentrations of the analyte. Presence of stray light.
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Smarajit Reply
4^×=9
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operation of trinomial
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y=2×+9
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