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We conclude that there is no answer to 4 ÷ 0 and so we say that division by 0 is undefined.

Division by zero

For any real number a , except 0, a 0 and a ÷ 0 are undefined.

Division by zero is undefined.

We summarize the properties of zero below.

Properties of zero

Multiplication by Zero: For any real number a ,

a · 0 = 0 0 · a = 0 The product of any number and 0 is 0.

Division of Zero, Division by Zero: For any real number a , a 0

0 a = 0 Zero divided by any real number, except itself is zero. a 0 is undefined Division by zero is undefined.

Simplify: −8 · 0 0 −2 −32 0 .

Solution


−8 · 0 The product of any real number and 0 is 0. 0


0 −2 Zero divided by any real number, except itself, is 0. 0


−32 0 Division by 0 is undefined. Undefined

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Simplify: −14 · 0 0 −6 −2 0 .

0 0 undefined

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Simplify: 0 ( −17 ) 0 −10 −5 0 .

0 0 undefined

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We will now practice using the properties of identities, inverses, and zero to simplify expressions.

Simplify: 0 n + 5 , where n 5 10 3 p 0 , where 10 3 p 0 .

Solution


0 n + 5 Zero divided by any real number except itself is 0. 0


10 3 p 0 Division by 0 is undefined. Undefined

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Simplify: −84 n + ( −73 n ) + 84 n .

Solution

−84 n + ( −73 n ) + 84 n Notice that the first and third terms are opposites; use the commutative property of addition to re-order the terms. −84 n + 84 n + ( −73 n ) Add left to right. 0 + ( −73 ) Add. −73 n

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Simplify: −27 a + ( −48 a ) + 27 a .

−48 a

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Simplify: 39 x + ( −92 x ) + ( −39 x ) .

−92 x

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Now we will see how recognizing reciprocals is helpful. Before multiplying left to right, look for reciprocals—their product is 1.

Simplify: 7 15 · 8 23 · 15 7 .

Solution

7 15 · 8 23 · 15 7 Notice the first and third terms are reciprocals, so use the commutative property of multiplication to re-order the factors. 7 15 · 15 7 · 8 23 Multiply left to right. 1 · 8 23 Multiply. 8 23

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Simplify: 9 16 · 5 49 · 16 9 .

5 49

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Simplify: 6 17 · 11 25 · 17 6 .

11 25

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Simplify: 0 m + 7 , where m 7 18 6 c 0 , where 18 6 c 0 .

0 undefined

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Simplify: 0 d 4 , where d 4 15 4 q 0 , where 15 4 q 0 .

0 undefined

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Simplify: 3 4 · 4 3 ( 6 x + 12 ) .

Solution

3 4 · 4 3 ( 6 x + 12 ) There is nothing to do in the parentheses, so multiply the two fractions first—notice, they are reciprocals. 1 ( 6 x + 12 ) Simplify by recognizing the multiplicative identity. 6 x + 12

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Simplify: 2 5 · 5 2 ( 20 y + 50 ) .

20 y + 50

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Simplify: 3 8 · 8 3 ( 12 z + 16 ) .

12 z + 16

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Simplify expressions using the distributive property

Suppose that three friends are going to the movies. They each need $9.25—that’s 9 dollars and 1 quarter—to pay for their tickets. How much money do they need all together?

You can think about the dollars separately from the quarters. They need 3 times $9 so $27, and 3 times 1 quarter, so 75 cents. In total, they need $27.75. If you think about doing the math in this way, you are using the distributive property .

Distributive property

If a , b , c are real numbers, then a ( b + c ) = a b + a c Also, ( b + c ) a = b a + c a a ( b c ) = a b a c ( b c ) a = b a c a

Back to our friends at the movies, we could find the total amount of money they need like this:

3 ( 9.25 ) 3 ( 9 + 0.25 ) 3 ( 9 ) + 3 ( 0.25 ) 27 + 0.75 27.75

In algebra, we use the distributive property to remove parentheses as we simplify expressions.

For example, if we are asked to simplify the expression 3 ( x + 4 ) , the order of operations says to work in the parentheses first. But we cannot add x and 4, since they are not like terms. So we use the distributive property, as shown in [link] .

Practice Key Terms 4

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Source:  OpenStax, Elementary algebra. OpenStax CNX. Jan 18, 2017 Download for free at http://cnx.org/content/col12116/1.2
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