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8.4 Rotation of axes

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In this section, you will:
  • Identify nondegenerate conic sections given their general form equations.
  • Use rotation of axes formulas.
  • Write equations of rotated conics in standard form.
  • Identify conics without rotating axes.

As we have seen, conic sections are formed when a plane intersects two right circular cones aligned tip to tip and extending infinitely far in opposite directions, which we also call a cone . The way in which we slice the cone will determine the type of conic section formed at the intersection. A circle is formed by slicing a cone with a plane perpendicular to the axis of symmetry of the cone. An ellipse is formed by slicing a single cone with a slanted plane not perpendicular to the axis of symmetry. A parabola is formed by slicing the plane through the top or bottom of the double-cone, whereas a hyperbola is formed when the plane slices both the top and bottom of the cone. See [link] .

The nondegenerate conic sections

Ellipses, circles, hyperbolas, and parabolas are sometimes called the nondegenerate conic sections , in contrast to the degenerate conic sections    , which are shown in [link] . A degenerate conic results when a plane intersects the double cone and passes through the apex. Depending on the angle of the plane, three types of degenerate conic sections are possible: a point, a line, or two intersecting lines.

Degenerate conic sections

Identifying nondegenerate conics in general form

In previous sections of this chapter, we have focused on the standard form equations for nondegenerate conic sections. In this section, we will shift our focus to the general form equation, which can be used for any conic. The general form is set equal to zero, and the terms and coefficients are given in a particular order, as shown below.

A x 2 + B x y + C y 2 + D x + E y + F = 0

where   A , B , and   C   are not all zero. We can use the values of the coefficients to identify which type conic is represented by a given equation.

You may notice that the general form equation has an   x y   term that we have not seen in any of the standard form equations. As we will discuss later, the   x y   term rotates the conic whenever   B   is not equal to zero.

Conic Sections Example
ellipse 4 x 2 + 9 y 2 = 1
circle 4 x 2 + 4 y 2 = 1
hyperbola 4 x 2 − 9 y 2 = 1
parabola 4 x 2 = 9 y  or  4 y 2 = 9 x
one line 4 x + 9 y = 1
intersecting lines ( x − 4 ) ( y + 4 ) = 0
parallel lines ( x − 4 ) ( x − 9 ) = 0
a point 4 x 2 + 4 y 2 = 0
no graph 4 x 2 + 4 y 2 =   −   1

General form of conic sections

A nondegenerate conic section    has the general form

A x 2 + B x y + C y 2 + D x + E y + F = 0

where   A , B , and   C   are not all zero.

[link] summarizes the different conic sections where   B = 0 , and   A   and   C   are nonzero real numbers. This indicates that the conic has not been rotated.

ellipse A x 2 + C y 2 + D x + E y + F = 0 ,   A ≠ C  and  A C > 0
circle A x 2 + C y 2 + D x + E y + F = 0 ,   A = C
hyperbola A x 2 − C y 2 + D x + E y + F = 0  or  − A x 2 + C y 2 + D x + E y + F = 0 , where   A   and   C   are positive
parabola A x 2 + D x + E y + F = 0  or  C y 2 + D x + E y + F = 0

Given the equation of a conic, identify the type of conic.

  1. Rewrite the equation in the general form, A x 2 + B x y + C y 2 + D x + E y + F = 0.
  2. Identify the values of   A   and   C   from the general form.
    1. If   A   and   C   are nonzero, have the same sign, and are not equal to each other, then the graph is an ellipse.
    2. If   A   and   C   are equal and nonzero and have the same sign, then the graph is a circle.
    3. If   A   and   C   are nonzero and have opposite signs, then the graph is a hyperbola.
    4. If either   A   or   C   is zero, then the graph is a parabola.

Questions & Answers

If c is the cost function for a particular product, find the marginal cost functions and their values at x=10 a. c(x) = 800+ 0.04x + 0.0002x² b. c(x) = 250 + 100x + 0.001x²
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when you reduce an equation to its simplest terms, you can't change the value of the equation. reducing it to y + 5 is equivalent to dividing it by 9 which changes the value. you can multiply it by 1 or 9/9 which would give 9(y + 5). multiplying it by one does not change the value.
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1. x + 6 2 -------------- = _ x + 9 + 6 3 x + 6 3 ----------- x -- (cross multiply) x + 15 2 3(x + 6) = 2(x + 15) 3x + 18 = 2x + 30 (-2x from both) x + 18 = 30 (-18 from both) x = 12 Test: 12 + 6 18 2 -------------- = --- = --- 12 + 9 + 6 27 3
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Source:  OpenStax, College algebra. OpenStax CNX. Feb 06, 2015 Download for free at https://legacy.cnx.org/content/col11759/1.3
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